Abstract
To obtain the total amount of precipitable water in mm, divide g cm−2 by g cm−3 and multiply by 10. So, for example, for 2 g cm−2, we have 20 mm of water. For a scale height of 2 km, to get from 10 mm water at sea level to 1 mm at elevation h, we have 1mm = 10 mm exp[-h/2000m] → h = —ln(0.l) × 2000 = 4600 m. Thus, the highest accessible mountain tops are just sufficient.
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© 2000 Springer-Verlag Berlin Heidelberg
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Wilson, T.L., Hüttemeister, S. (2000). Solutions for Chapter 8. In: Tools of Radio Astronomy. Astronomy and Astrophysics Library. Springer, Berlin, Heidelberg. https://doi.org/10.1007/978-3-642-57001-8_22
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DOI: https://doi.org/10.1007/978-3-642-57001-8_22
Publisher Name: Springer, Berlin, Heidelberg
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