Solutions

Abstract

2.1 NMR Master EquationTo apply (2.8) the linear frequency has to be transformed into angular frequency:

$$\gamma = \frac{2\pi \nu } {{B}_{0}} = \frac{2\pi \,200.13 \times 1{0}^{6}\,\mathrm{Hz}} {4.7\,\mathrm{T}} = 2.675 \times 1{0}^{8}\,{\mathrm{rad\,s}}^{-1}\,{T}^{-1}.$$

For other nuclei see list of constants on p. xviii.