Abstract
If a force Q acts along axis z (Fig. 3.1) we have from (2.56) a simple equation
with an obvious solution τr = C/r where C = –Q/2π from the equilibrium equation ΣZ = 0 of the part of the cylinder in Fig. 3.1. Using the Hooke’s law (2.51) and the first expression (2.57) we can write the final result as follows
where uo is a constant.
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© 2009 Springer-Verlag Berlin Heidelberg
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Elsoufiev, S.A. (2009). Some Elastic Solutions. In: Strength Analysis in Geomechanics. Springer Series in Geomechanics and Geoengineering. Springer, Berlin, Heidelberg. https://doi.org/10.1007/978-3-642-01301-0_3
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DOI: https://doi.org/10.1007/978-3-642-01301-0_3
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