Abstract
In previous chapters, we exploited the symbolic method to study the behavior of electrical circuits with sinusoidal voltages and currents.
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Notes
- 1.
A generic signal shape is only preserved in the particular case of circuit consisting uniquely of resistances.
- 2.
We have already seen in Sect. 5.3.2 that circuits with capacitance and inductance are described by differential equations.
- 3.
See Sect. 6.8.
- 4.
The first-order linear differential equation \(y'(t)=\alpha (t)y(t)+\beta (t)\) has for general solution:
$$\begin{aligned} y(t)=\exp \left( \int _0^t \alpha (\tau )\, d\tau \right) \left[ c +\int _0^td\tau \,\beta (\tau )\exp \left( -\int _0^\tau \alpha (\tau ')\, d\tau '\right) \right] \end{aligned}$$where c is the integration constant. If, as of interest in our case, \(\alpha (t)\) and \(\beta (t)\) are constants (\(\alpha (t)=\alpha _o\) and \(\beta (t)=\beta _o\)), the previous relation simplifies to
$$\begin{aligned} y(t)=\left( c+\beta _o/\alpha _o\right) \exp \left( \alpha _o t\right) -{\beta _o}/{\alpha _o} \end{aligned}$$For Eq. (9.3) we have \(\alpha _o=-1/RC\) and, requiring \(y(\infty )=V_f\) and \(y(0)=V_i\), we get \(\beta _o/\alpha _o=V_f\) and \(c=(V_i-V_f)\).
- 5.
This expression means that the property enunciated is not verified only for a set of points of zero measure.
- 6.
The capacitors used to block the direct current flow are called blocking capacitors.
- 7.
This signal has already been described in Sect. 7.2.3.
- 8.
The proof of this statement has already been given in a previous chapter in the frequency domain (see Sect. 7.3). The proof, by means of the Fourier series expansion, shows that the AC coupling, made through a high-pass RC filter, turns any periodic signal into an alternating signal, with zero average.
- 9.
The same characteristic property was highlighted in the analysis of this circuit in the frequency domain. See Sect. 6.10.
- 10.
See p. 201 for details.
- 11.
The same characteristic was highlighted in the analysis of this circuit in the frequency domain. See Sect. 6.10.
- 12.
Note that we already encountered this equation in studying the motion of the movable coil in the D’Arsonval ammeter; obviously, owing to the similarity of the two differential equations, the solution we obtain in this section are qualitatively similar to those obtained in Sect. 4.3.2 for the position of the moving coil.
- 13.
Note that k and \(T_o\) have already been introduced in the analysis of the resonant circuit RLC parallel (Chap. 6). In fact \(k=1/2Q_p\), where \(Q_p\) is the quality factor of the circuit and \(T_o\) is exactly the period corresponding to the resonant frequency of the circuit.
- 14.
The time \(\tau _L=R/L\) is the characteristic times of the circuit shown in Fig. 9.14 for \(C\rightarrow \infty \) (this means that this circuit behaves like a high-pass RL), and similarly the time \(\tau _C=RC\) is the characteristic times of the circuit for \(L\rightarrow 0\) (this means that this circuit behaves like a low-pass RC).
- 15.
For example, this is the case when \(R_2\) represents the input resistance of a measuring instrument. In fact any real device has a finite value of the input capacitance. The input capacitance of oscilloscopes varies in the range 15–50 pF. Furthermore, the connection cables between the attenuator and the measuring instrument add a capacitance of the order of 100 pF/m and an inductance of the order of \(0.1\,\upmu \)H/m.
- 16.
Oscilloscope probes consist of a compensated voltage divider were \(R_2\) is the input resistance of the instrument and \(C_2\) its stray input capacitance. Resistance \(R_1\) and capacitance \(C_1\) depend upon the attenuation factor of the probe. Capacitor \(C_1\) is variable and is adjusted to compensate the probe response.
- 17.
Note that, from a mathematical point of view, at \(t=0\) also the current has a discontinuity and through the capacitors flow an “infinite” current that loads them instantaneously. More realistic physical considerations will be made in the following.
- 18.
We remind that the derivative of \(v_g(t)\) proportional to the \(\theta (t)\) function is zero “almost everywhere”.
- 19.
Oscilloscope probes are compensated minimizing the slow component of their response to a square wave calibration pulse supplied by the instrument.
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Problems
Problems
Problem 1
A: Obtain the differential equation for the output voltage \(v_o(t)\) across the inductance L of the RL circuit shown in Fig. 9.11a when the input voltage is \(v_i(t)\). B: Determine under what conditions the voltage \(v_o(t )\) is proportional to the derivative of \(v_i(t)\) in the case the input signal is a pulse of duration \(\tau \). C: Solve the differential equation found in A in the case \(v_i(t)\) is a voltage step function of amplitude V using appropriate initial conditions. [A. A: \(dv_i(t)/dt=(R/L)v_L(t)+dv_L(t)/dt\); B: \((L/R)\ll \tau \); C: \(v_L(t)=V\exp (-Rt/L)\).]
Problem 2
A: Obtain the differential equation for the output voltage \(v_o(t)\) across the resistance R of the RL circuit shown in Fig. 9.11b when the input voltage is \(v_i(t)\) B: Determine under what conditions the voltage \(v_R(t )\) is proportional to the integral of \(v_i(t)\) in the case the input signal is a pulse of duration \(\tau \). C: Solve the differential equation found in A in the case \(v_i(t)\) is a voltage step function of amplitude V using appropriate initial conditions. [A. A: \(v_i(t)=(L/R)v_R(t)+dv_R(t)/dt\); B: \((L/R)\ll \tau \); C: \(v_R(t)=V(1-\exp (-Rt/L)\)).]
Problem 3
In the circuit shown in the figure the switch T is open at time \(t=0\). Determine the voltage across the capacitance C as a function of time. [A. \(v_C(t)=V_1+(V_2-V_1)\exp (-t/RC)\).]
Problem 4
Obtain the differential equation for the voltage v(t) across the capacitance C of the circuit shown in the figure. Solve the differential equation when \(v_i\) is a voltage step function of amplitude V. [A. \(v(t)=VR_2/(R_1+R_2)\exp (-t (R_1+R_2)/(R_1R_2C))\).]
Problem 5
Solve the previous problem using the Thévenin’s theorem.
Problem 6
In the circuit shown in the figure the switch T is closed at time \(t=0\). Determine the voltage across the capacitance C as a function of time. [A. \(v(t)=VR_3/(R_1+R_3)\exp (-t(R_3+R_1)/(R_3C(R_1+R_2+R_1R_2/R_3)))\).]
Problem 7
Solve the previous problem using the Thévenin’s theorem
Problem 8
Obtain the differential equation for the current \(i_L(t)\) through the inductance L in the circuit shown in the figure, when \(v_i(t)\) is the input voltage. [A. \(v_i(t) R_3(R_1R_3+R_1R_2+R_2R_3)=i_L+L(R_1+R_3)/((R_1R_3+R_1R_2+R_2R_3)di_L/dt\).]
Problem 9
Solve the previous problem using the Norton’s theorem
Problem 10
Obtain the differential equation for the voltage \(v_C(t)\) across the capacitance C in a RLC series circuit when \(v_i(t)\) is the input voltage. Solve the differential equation, using the appropriate boundary conditions, when \(v_i\) is a voltage step function of amplitude V. [A. \(v_i(t)=v_C(t)+RCdv_C(t)/dt+LCd^2v_C(t)/dt^2\); \(v_C(0)=0, dv_C/dt(0)=0\).]
Problem 11
As an alternative to the exponential pulse, a real voltage step can be described as a linear ramp of time duration T up to the constant value V. Using the convolution method, find the response of a high-pass RC circuit to this input waveform. Comment the solution obtained in terms of the behavior of the capacitor C. [A. \(v_o(t) = 0\,\text {for}\,\,t<0, \quad v_o(t)=\alpha RC[1-\exp (-t/RC)]\,\,\, \text{ for }\,\,0 < t <T,v_o(t) = \alpha RC[1-\exp (-T/RC)] \exp [-(t-T)/RC] \quad \text{ for } t >T\).]
Problem 12
The circuit shown in the figure represents a real RL filter where the inductor L has a stray resistance \(R_L\). Obtain the differential equation for the current \(i_L(t)\) through the inductance L in response of an input voltage \(v_i(t)\). Solve the differential equation when \(v_i\) is a voltage step function of amplitude V. Finally obtain the output voltage \(v_o(t)\) across the real inductor. [A. \(v_o(t)=VR_L/(R+R_L)+VR/(R+R_L)exp(-t/\tau )\) with \(\tau =L/(R+R_L)\).]
Problem 13
In the circuit shown in the figure the switch T is closed at time \(t=0\). Obtain the differential equation for the current \(i_L(t)\) in the inductance L as a function of time and determine the appropriate boundary conditions for the solution. [A. \(V=R_1 i_L(t)+(L+R_1R_2C)di_L(t)/dt+R_1LCd^2i_L(t)/dt^2\) where \(i_L(0)= V/(R_1+R_2)\), \(di_L/dt(0)=V/L(R_1+R_2)\).]
Problem 14
The circuit in the figure is a diagram of the cable connection of a signal to an oscilloscope. Derive in time domain the differential equation yielding the signal \(v_o(t)\) across the resistance \(R_2\) when the input signal is \(v_i(t)\). Find the appropriate boundary conditions for the solution when the input is a voltage step function. [A. \(v_i(t)=(1+R_1/R_2)v_o(t)+(R_1C+L/R_2)dv_o(t)/dt+LCd^2v_o(t)/dt^2\); \(v_o(0)=0,\, dv_o/dt(0)=0\).]
Problem 15
The circuit in the figure represents a filter LR realized with a real inductor whose series resistance is \(R_L\) and whose parasitic capacitance is C. Obtain the differential equation that describes the response \(v_o(t)\) to a signal \(v_i(t)\). Find the appropriate boundary conditions in case the input signal is a step function of amplitude V. [A. \(v_i(t)+RCdv_i(t)/dt+LCd^2v_i(t)/dt^2=(1+R_L/R)v_o(t)+(RC+L/R)dv_o(t)/dt+LCd^2v_o(t)/dt^2\); \(v_o(0)=V, dv_o/dt(0)=-V/RC\).]
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Bartiromo, R., De Vincenzi, M. (2016). Pulsed Circuits. In: Electrical Measurements in the Laboratory Practice. Undergraduate Lecture Notes in Physics. Springer, Cham. https://doi.org/10.1007/978-3-319-31102-9_9
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DOI: https://doi.org/10.1007/978-3-319-31102-9_9
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