Abstract
This chapter covers power-supply design. It turns out that power supplies source both DC and AC current. That a DC power supply sources AC current is surprising, but is a consequence of the fact that signal-value changes are an AC phenomenon. As a result, a DC power supply is actually modeled in the frequency domain.
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Homework
Homework
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1.
Construct a power infrastructure for a simple design. The design as a target Xmax of 0.1 Ω, a risetime of 500 ps, and a power-and-ground-plane capacitance of 1500 pF.
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Write down the last 4 digits of your student ID number:
$$ \begin{array}{ccccc}\hfill \mathrm{Digit}:\hfill & \hfill \frac{}{\kern1em \mathrm{A}\kern1em }\hfill & \hfill \frac{}{\kern1em \mathrm{B}\kern1em }\hfill & \hfill \frac{}{\kern1em \mathrm{C}\kern1em }\hfill & \hfill \frac{}{\kern1em \mathrm{D}\kern1em }\hfill \end{array} $$ -
Replace any instances of “0” with the last nonzero digit in your student ID number:
$$ \begin{array}{ccccc}\hfill \mathrm{Digit}:\hfill & \hfill \frac{}{\kern1em \mathrm{A}\kern1em }\hfill & \hfill \frac{}{\kern1em \mathrm{B}\kern1em }\hfill & \hfill \frac{}{\kern1em \mathrm{C}\kern1em }\hfill & \hfill \frac{}{\kern1em \mathrm{D}\kern1em }\hfill \end{array} $$ -
Power-supply inductance is D*25 nH.
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Inductance of bypass cap, L byp, is C nH.
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Resistance of bypass cap, R byp, is X max/2 = 0.05 Ω.
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Inductance of a single array capacitor, L cap, is B nH.
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Resistance of a single array capacitor, R cap, is A/10 Ω.
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(a)
Compute f psw, the point at which the power-supply wiring has too much impedance.
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(b)
Compute C byp, the amount of bypass capacitance needed.
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(c)
Compute f byp, the point at which the bypass capacitance has too much impedance.
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(d)
Compute N, the number of array capacitors needed.
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(e)
Compute C cap, the capacitance value of each array capacitor.
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(f)
Compute Rarray and Larray, the resistance and inductance of the entire capacitor array, taking into account that there are N capacitors in parallel.
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(g)
For the resonance between the capacitor array and the power and ground planes, compute the frequency of resonance and the impedance at the resonance.
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2.
Use the component values you calculated in Part 1 to construct a SPICE simulation of the power infrastructure. For the array, you can assume the parallel combination of the R, L, and C. Run an AC sweep of the structure from 1 kHz to 10 GHz. One efficient way to do this is to create a 1 Amp AC current source and measure the voltage. Under these circumstances, the voltage is equal to the impedance. Do the results match your calculations in Part 1?
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Russ, S.H. (2016). Power Distribution Network: Frequency Domain Analysis. In: Signal Integrity. Springer, Cham. https://doi.org/10.1007/978-3-319-29758-3_10
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DOI: https://doi.org/10.1007/978-3-319-29758-3_10
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Publisher Name: Springer, Cham
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Online ISBN: 978-3-319-29758-3
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