Abstract
Let B = (B t)t≥o be standard Brownian motion started at zero. Then the following inequality is shown to be satisfied:
for all stopping times τ for B, all 0 < p < 1 + q, and all q > 0, with the best possible value for the constant being equal:
where k = p/(q-p + l), and s* is the zero point of the (unique) maximal solution s ↦,g* (s) of the differential equation:
satisfying 0 < g*(s) < s for all s > s*, where α = q/p — 1, β = 1/p and K = p/2. This solution is also characterized by g*(s)/s → 1 for s → ∞. The equality above is attained at the stopping time:
where X t = |B t|p and \({S_t} = {\max _{0 \le r \le t}}|{B_r}{|^p}\). In the case p = 1 the closed form for s ↦ g*(s) is found. This yields \(\mathop \gamma \nolimits_{1,q}^* = {\left( {q\left( {q + 1} \right)/2} \right)^{1/\left( {q + 1} \right)}}{\left( {\Gamma \left( {1 + \left( {q + 1} \right)/q} \right)} \right)^{q/\left( {q + 1} \right)}}\) for all q > 0. In the case p ≠ 1 no closed form for s ↦ g*(s) seems to exist. The inequality above holds also in the case p = q +1 (Doob’s maximal inequality). In this case the equation above ( with K = p/2c ) admits g* (s) = λs as the maximal solution, and the equality is attained only in the limit through the stopping times τ* = τ* (c) when c tends to the best value \(\mathop \gamma \nolimits_{q + 1,q}^* = {\left( {q + 1} \right)^{q + 2}}/2{q^q}\) from above. The method of proof relies upon the principle of smooth fit of Kolmogorov and the maximality principle. The results obtained extend to the case when B starts at any given point, as well as to all non-negative submartingales.
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Peškir, G. (1998). The Best Doob-Type Bounds for the Maximum of Brownian Paths. In: Eberlein, E., Hahn, M., Talagrand, M. (eds) High Dimensional Probability. Progress in Probability, vol 43. Birkhäuser, Basel. https://doi.org/10.1007/978-3-0348-8829-5_18
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