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Abstract

Traditionally, mechanical engineering design has been based almost entirely on the use of ductile metals. They are tough, are relatively strong, and can readily be formed into complicated shapes. A great deal of research has been devoted to the processing and mechanical behavior of these materials, and design methods for their use are rather well established. By contrast, relatively little attention has been given, in the past, by mechanical engineers, to materials showing brittle behavior. Civil engineers have used such materials, but generally in situations where they are in compression and with generous safety factors being allowed. In recent years, however, there has been an increasing interest in the use of brittle solids in engineering design. Perhaps the principal reason for this is that the materials which have the greatest strength at very high temperatures are brittle at ambient temperature, for example, graphite, aluminum oxide, beryllium oxide, silicon carbide, and silicon nitride. If such materials could be fabricated and used, reliably, the economic advantages would be considerable in many high-temperature applications. The usefulness of brittle materials is, of course, not confined to elevated temperatures. In many other situations, the properties of specific brittle materials (e.g., wear and corrosion resistance, high compressive strength, low neutron absorption in the case of BeO, transparency in the case of quartz and glass, etc.) make them attractive to the designer.

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Notes

  1. 1.

    Variability in strength is an inherent feature of brittle solids although it may also be influenced by faulty testing techniques. One should be cautious in evaluating novel techniques which purport to reduce variability in testing brittle solids. Such tests have been reported in the literature based on a very small number of specimen and with high and low strength values having been discarded by an overly helpful laboratory assistant.

  2. 2.

    By contrast to polycrystalline ceramics where the strength impairing flaws are distributed throughout the volume of a part, in glass the flaws are apparently confined to the surface. Very few cases of internal failure in glass have been reported. Carefully prepared glass rods are greatly degraded in strength when subjected to surface damage such as sandblasting. On the other hand, etching away a surface layer with hydrofluoric acid, flame polishing, or the presence of residual compressive stresses may greatly increase the strength of glass parts. These observations, the variability in strength, and the discrepancy between observed strengths and the theoretical value are strong indirect evidence for the presence of “Griffith” cracks. However, to our knowledge there has, as yet, been no direct observation of the inherent flaws in glass.

    Taking \( {G}_{Ic}\cong 0.03\;\mathrm{in}-\mathrm{lb}/{\mathrm{in}}^2 \), E = 107 psi, and the strength of such glass as 104 psi, from the thumbnail flaw solution, we would expect a maximum crack depth of about 10−3 in if the cracks were shallow scratches. The resolution R of an optical microscope is given by \( R\cong \mathrm{Wavelength}\ \mathrm{of}\ \mathrm{light}/\left(\mathrm{refracture}\ \mathrm{index}, \sin U\right) \) where 2U is the solid angle at which light passes into the objective lens. In the best case with \( \sin U\cong 0.95 \), violet light and oil immersion, \( R\cong \frac{6\times 4\times {10}^{-5}}{1.6\times 0.95}\cong 1.6\times {10}^{-5}\ \mathrm{cm} = 0.16\;\mu . \)

    Thus we conclude that the crack faces must be closed. Presumably this accounts for the lack of success of electron microscope observations since the replicas could then not penetrate the cracks.

    However, what has been done is to expose the glass at elevated temperature to sodium vapor. A thin layer of high expansion coefficient glass is formed, and on cooling, tensile stresses are produced which form a crack pattern like drying mud. This pattern appears to initiate at preexisting surface flaws for if the glass is etched first with hydrofluoric acid, no crack pattern appears.

  3. 3.

    Strictly speaking in using Eq. (8.4), we must assume that the number of flaws is large enough for distribution of the weakest values to converge to G(σ) but is still small enough so that the flaws do not interact. Whether this assumption will be violated in a given case will depend on the flaw strength distribution F(σ) and the stress level involved. For example, if F(σ) itself should be a Weibull distribution, we do not have to specify that there should be a large number of flaws.

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Problems

Problems

  1. 1.

    A series of ten tensile tests on a brittle solid gave the following values:

    $$ \begin{array}{l}\kern0.55em 6,600,\kern1.45em 8,070,\kern1.5em 8,900,\kern1.5em 9,500,\kern1.5em 9,830\kern0.37em \mathrm{psi}\\ {}10,350,\kern1em 10,890,\kern1em 11,350,\kern1em 11,920,\kern1em 12,570\kern0.37em \mathrm{psi}\end{array} $$

    The mean strength is 10,000 psi and the standard deviation is 1,820 psi.

    Assuming that a 2-parameter Weibull distribution can be fitted to these values, estimate m in several different ways.

    Can you make an estimate of the lowest strength that would be observed if 100 such specimens were tested?

    If a new set of specimens is prepared with the specimen volume ten times that of the original specimens, what do you estimate as the mean strength of the larger specimens?

  2. 2.

    We consider tension tests on a specimen of rectangular cross-section. If the loading axis is parallel to the geometrical axis of the specimen, but eccentric by distance ε, then the specimen is subjected to a force P and a moment P ε. Thus, the maximum tensile stress in the specimen is

    $$ {\sigma}_{\max }=\frac{P}{bh}+\frac{6P\varepsilon }{b{h}^2} $$
    1. (a)

      For a brittle solid containing flaws distributed through its volume in which the probability of failure of unit volume may be taken as

      $$ F\left(\sigma \right)=1-{e}^{-{\left(\sigma /{\sigma}_0\right)}^m}, $$

      you are asked to obtain an expression for the ratio:

      $$ \frac{\mathrm{Median}\ \mathrm{fracture}\ \mathrm{load}\ \left(\varepsilon =h/6\right)}{\mathrm{Median}\ \mathrm{fracture}\ \mathrm{load}\ \left(\varepsilon =0\right)} $$
    2. (b)

      Compare this result with the ratio of fracture loads (for \( \varepsilon =\mathrm{h}/6 \) and \( \varepsilon =\theta \)) which would be predicted for a brittle material with no variability in strength. Explain physically why the ratios differ.

      figure a
  3. 3.

    Consider the pure bending of a beam of rectangular cross section of a brittle solid. Assuming that fracture under tensile states of stress may be predicted using a two-parameter Weibull distribution, you are asked to obtain an expression for the median value of moment required to fracture the beam. That is, \( {M}_{\mathrm{median}}=f\left(b,h,L,{\sigma}_0,m\right) \). Recall that the stress at a distance y from the neutral axis is given by \( \sigma =\frac{My}{I} \).

    figure b
  4. 4.

    A frequently used design rule specifies that the strength value used in structural calculations should be taken as Mean Strength − 3 Standard Deviations. This rule, apparently, is based on the assumption that the strength values follow a Normal Distribution. In any event, if we are dealing with brittle solids, whose strength values follow a two-parameter Weibull Distribution say with m = 10, would this design rule overestimate or underestimate the strength of the weakest specimen in a batch of size N?

  5. 5.

    In testing short whiskers of a brittle material, the ends are embedded in a low strength matrix to which the loading is applied. As a result, the stress at each end of the whisker increases linearly over a length l from zero to the value σ g . The stress σ g is that in the “gauge length” L. If L is short, many whiskers will break in the grips and we do not want to discard these observations. For this reason, you are asked to derive an expression for the cumulative distribution function G(σ) (i.e., probability that a given whisker will break at or below a gauge section stress level σ g ) which includes the probability of failure occurring in the grips. From this result can you suggest a simple expression for the effective gauge length in such a test.

    We assume that flaws are distributed along the length of these whiskers rather than volume or area and use a two-parameter Weibull distribution.

    figure c
  6. 6.

    A bundle is made from a large number of filaments. The individual filaments show a great deal of variability and their breaking loads follow an exponential distribution. That is, the survival probability is given by \( S(x)={e}^{-\lambda x} \) where λ is the one parameter of the exponential distribution.

    What fraction of the filaments will survive at the maximum load-carrying capacity of the bundle?

    What is the average fracture load which would be observed in testing single filaments (expressed in terms of λ)?

  7. 7.

    Tests on ten glass filaments gave the following values of fracture load in pounds 6.1, 6.5, 8.5, 9.2, 11.5, 14.0, 15.0, 25.0, 30.0, 32.0 (the average is 15.8 lb).

    What would have been the maximum load-carrying capacity if these ten filaments had been tested as a bundle.

    It has been suggested that very strong bundles could be obtained by proof testing all filaments such that we discard all but the strongest 20 %.

    You are asked to predict the ratio: Strength of a bundle made from the survivors of such a proof test ÷ Strength of a bundle made from filaments that have not been proof tested. Both bundles are assumed to have the same (large) number of filaments.

  8. 8.

    Assuming a volume distribution of flaws, a 2-parameter Weibull distribution has been obtained for a granitic rock. The values are m = 13 and \( {\sigma}_0=1,200\kern0.37em \left(\mathrm{psi}\hbox{-} \mathrm{in}.\ \mathrm{units}\right) \).

    You are asked to consider a test in which a cylindrical hole of radius R j in a very large diameter cylindrical block of length L is pressurized. Assuming that the pressure P cannot penetrate any cracks present at the bore, you are asked to obtain an expression for the median pressure to produce fracture. Ignore radial and axial stresses and take the hoop stress as \( {\sigma}_{\theta }=p{\left({R}_j/r\right)}^2 \). First, obtain a general result \( \left(p\kern0.5em \mathrm{median}/{\sigma}_0\right)=f\left(\dot{m},{R}_j,L\right) \). Then specialize this for m = 13, \( {\sigma}_0=1,200 \), R = 0.5 in., L = 10 in.

  9. 9.

    Three sets of bending tests were made on specimens of a brittle solid of three different sizes. The results were:

     

    Tests A (15 specimens)

    Tests B (4 specimens)

    Tests C (4 specimens)

    Strength (psi)

    1,587, 1,801, 1,923

    1,835, 2,163

    2,028, 2,062

    1,954, 1,623, 1,863

    2,190, 2,274

    2,428, 2,616

    1,923, 2,015, 1,679

    1,863, 1,953, 2,137

    1,709, 1,893, 1,953

    Average strength (psi)

    1,858

    2,116

    2,283

    You are asked to use all this information to make an estimate of the Weibull parameter m for this material. One general approach for estimating m is sufficient.

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Dharan, C.K.H., Kang, B.S., Finnie, I. (2016). The Fracture of Brittle Solids. In: Finnie's Notes on Fracture Mechanics. Springer, New York, NY. https://doi.org/10.1007/978-1-4939-2477-6_8

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  • DOI: https://doi.org/10.1007/978-1-4939-2477-6_8

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