Man nehme an, die Zahl e genüge der Gleichung n
ten Grades
EquationSource% MathType!MTEF!2!1!+-
% feaagCart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyaiabgU
% caRiaadggadaWgaaWcbaGaaGymaaqabaGccaWGLbGaey4kaSIaamyy
% amaaBaaaleaacaaIYaaabeaakiaadwgadaahaaWcbeqaaiaaikdaaa
% GccqGHRaWkcqWIVlctcqGHRaWkcaWGHbWaaSbaaSqaaiaad6gaaeqa
% aOGaamyzamaaCaaaleqabaGaamOBaaaakiabg2da9iaaicdaaaa!48A9!]]</EquationSource><EquationSource Format="TEX"><![CDATA[$$a + {a_1}e + {a_2}{e^2} + \cdots + {a_n}{e^n} = 0$$
,
deren Coefficienten a, a
1, ..., a
n
ganze rationale Zahlen sind. Wird die linke Seite dieser Gleichung mit dem Integral
EquationSource% MathType!MTEF!2!1!+-
% feaagCart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaa8qmaeaacq
% GH9aqpaSqaaiaaicdaaeaacqGHEisPa0Gaey4kIipakmaapedabaGa
% amOEamaaCaaaleqabaGaeqyWdihaaOWaamWaaeaadaqadaqaaiaadQ
% hacqGHsislcaaIXaaacaGLOaGaayzkaaWaaeWaaeaacqaHvpGzcqGH
% sislcaaIYaaacaGLOaGaayzkaaGaaiOlaiaac6cacaGGUaWaaeWaae
% aacaWG6bGaeyOeI0IaamOBaaGaayjkaiaawMcaaaGaay5waiaaw2fa
% amaaCaaaleqabaGaeqyWdiNaey4kaSIaaGymaaaakiaadwgadaahaa
% WcbeqaaiabgkHiTiaadQhaaaGccaWGKbGaamOEaaWcbaGaaGimaaqa
% aiabg6HiLcqdcqGHRiI8aaaa!5CC5!]]</EquationSource><EquationSource Format="TEX"><![CDATA[$$\int_0^\infty = \int_0^\infty {{z^\rho }{{\left[ {\left( {z - 1} \right)\left( {\phi - 2} \right)...\left( {z - n} \right)} \right]}^{\rho + 1}}{e^{ - z}}dz} $$
multiplicirt, wo ρ eine ganze positive Zahl bedeutet, so entsteht der Ausdruck
EquationSource% MathType!MTEF!2!1!+-
% feaagCart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyyamaape
% dabaGaey4kaScaleaacaaIWaaabaGaeyOhIukaniabgUIiYdGccaWG
% HbWaaSbaaSqaaiaaigdaaeqaaOGaamyzamaapedabaGaey4kaScale
% aacaaIWaaabaGaeyOhIukaniabgUIiYdGccaWGHbWaaSbaaSqaaiaa
% ikdaaeqaaOGaamyzamaaCaaaleqabaGaaGOmaaaakmaapedabaGaey
% 4kaScaleaacaaIWaaabaGaeyOhIukaniabgUIiYdGccqWIVlctcqGH
% RaWkcaWGHbWaaSbaaSqaaiaad6gaaeqaaOGaamyzamaaCaaaleqaba
% GaamOBaaaakmaapedabaaaleaacaaIWaaabaGaeyOhIukaniabgUIi
% Ydaaaa!5857!]]</EquationSource><EquationSource Format="TEX"><![CDATA[$$a\int_0^\infty + {a_1}e\int_0^\infty + {a_2}{e^2}\int_0^\infty + \cdots + {a_n}{e^n}\int_0^\infty $$
und dieser Ausdruck zerlegt sich in die Summe der beiden folgenden Ausdrücke:
EquationSource% MathType!MTEF!2!1!+-
% feaagCart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn
% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr
% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9
% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x
% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaacaWGqb
% WaaSbaaSqaaiaaigdaaeqaaOGaeyypa0JaamyyamaapedabaGaey4k
% aSIaamyyamaaBaaaleaacaaIXaaabeaakiaadwgadaWdXaqaaiabgU
% caRiaadggadaWgaaWcbaGaaGOmaaqabaaabaGaaGimaaqaaiabg6Hi
% LcqdcqGHRiI8aaWcbaGaaGimaaqaaiabg6HiLcqdcqGHRiI8aOGaam
% yzamaaCaaaleqabaGaaGOmaaaakmaapedabaGaey4kaSIaeS47IWKa
% ey4kaScaleaacaaIWaaabaGaeyOhIukaniabgUIiYdGccaWGHbWaaS
% baaSqaaiaad6gaaeqaaOGaamyzamaaCaaaleqabaGaamOBaaaakmaa
% pedabaGaaiilaaWcbaGaaGimaaqaaiabg6HiLcqdcqGHRiI8aaGcba
% GaamiuamaaBaaaleaacaaIYaaabeaakiabg2da9iaadggadaWgaaWc
% baGaaGymaaqabaGccaWGLbWaa8qmaeaacqGHRaWkcaWGHbWaaSbaaS
% qaaiaaikdaaeqaaOGaamyzamaaCaaaleqabaGaaGOmaaaakmaapeda
% baGaey4kaSIaeS47IWKaey4kaSIaamyyamaaBaaaleaacaWGUbaabe
% aakiaadwgadaahaaWcbeqaaiaad6gaaaGcdaWdXaqaaiaac6caaSqa
% aiaaicdaaeaacaWGUbaaniabgUIiYdaaleaacaaIWaaabaGaaGOmaa
% qdcqGHRiI8aaWcbaGaaGimaaqaaiaaigdaa0Gaey4kIipaaaaa!7984!]]</EquationSource><EquationSource Format="TEX"><![CDATA[$$\begin{gathered} {P_1} = a\int_0^\infty { + {a_1}e\int_0^\infty { + {a_2}} } {e^2}\int_0^\infty { + \cdots + } {a_n}{e^n}\int_0^\infty, \hfill \\ {P_2} = {a_1}e\int_0^1 { + {a_2}{e^2}\int_0^2 { + \cdots + {a_n}{e^n}\int_0^n . } } \hfill \\ \end{gathered} $$
.