On page 72, Table 3.5 has the forms of 3rd rank tensors for all the crystallographic point groups. Five of these have factors of 2 in some of the components. These factors of 2 can be found in other published tables of 3rd rank tensors but they are only valid for a different type of notation that is not used in the book. To be consistent with the tensor notation used throughout this book, no factors of 2 should appear in these tensors. The Erratum provides a corrected Table 3.5 with the factors of 2 eliminated from all the tensor elements.

In addition, on page 73 an example is given in the second paragraph using one of the tensors from Table 3.5 that contains erroneous factors of 2 in some of its components. The Erratum provides a corrected paragraph without the factors of 2.

Table III.5 Form of third rank tensors for the crystallographic point groups.

Page 73, second paragraph

As a practical example, consider a quartz crystal that has D3 symmetry at room temperature. The piezoelectric effect for this case is given by

$$ \left(\begin{array}{c}\hfill {P}_1\hfill \\ {}\hfill {P}_2\hfill \\ {}\hfill {P}_3\hfill \end{array}\right)=\left[\begin{array}{ccc}\hfill {d}_{111}\hfill & \hfill 0\hfill & \hfill 0\hfill \\ {}\hfill 0\hfill & \hfill -{d}_{111}\hfill & \hfill d{}_{132}\hfill \\ {}\hfill 0\hfill & \hfill {d}_{132}\hfill & \hfill 0\hfill \\ {}\hfill 0\hfill & \hfill -{d}_{111}\hfill & \hfill -{d}_{132}\hfill \\ {}\hfill -{d}_{111}\hfill & \hfill 0\hfill & \hfill 0\hfill \\ {}\hfill -{d}_{132}\hfill & \hfill 0\hfill & \hfill 0\hfill \\ {}\hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill \\ {}\hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill \\ {}\hfill 0\hfill & \hfill 0\hfill & \hfill 0\hfill \end{array}\right]\left(\begin{array}{ccc}\hfill {\sigma}_{11}\hfill & \hfill {\sigma}_{12}\hfill & \hfill {\sigma}_{13}\hfill \\ {}\hfill {\sigma}_{21}\hfill & \hfill {\sigma}_{22}\hfill & \hfill {\sigma}_{23}\hfill \\ {}\hfill {\sigma}_{31}\hfill & \hfill {\sigma}_{32}\hfill & \hfill {\sigma}_{33}\hfill \end{array}\right) $$

.

so

  • P 1=d111σ11–d111σ22+d132σ32+d132σ23=(σ11-σ22)d111+(σ32+σ23)d132

  • P 2= -d111σ21–d132σ31-d111σ12-d132σ13= -d111(σ21+σ12)-(σ13+σ31)d132

  • P 3=0

If a uniaxial stress is applied in the σ11 direction, P 1=d111σ11 and P2=0. The same tensile stress applied along σ22 also produces a polarization along P 1. The two-fold rotation axis P 1 is the electric axis of quartz. Shear stress can produce polarization along P 2 but no stress conditions can produce a polarization along P 3.