Induction and Exhaust Processes

Abstract

In the first case with 2 valves (one inlet and one exhaust), the perimeter (P ₂ ) is:

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In the second case with 4 valves (two inlet and two exhaust), the perimeter (P ₄ ) is:

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The percentage increase in valve perimeter is: 100 x (P ₄ − P ₂ )/ P ₂ = 100 x (116.24 − 72.26)/72.26 = 60.86% Using the valve curtain area (A _c )to define the flow area: $$ where the valve life (L) is L = kd Thus:

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and:

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The increase in valve curtain area is: (A _c,4 − A _c,2 )/A _c,2 = (2150 − 1662)/1662 = 0.29, or 29%