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Solutions

  • Satish Shirali
  • Harkrishan Lal Vasudeva
Chapter

Abstract

Therefore some subsequence has every term in K j . Since K j is compact, it follows that the subsequence has a subsequence converging to a limit in K j , which must then belong to the union K. But this subsequence is itself a subsequence of the sequence that we started with. The latter is therefore seen to have a subsequence converging to a limit in K.

Keywords

Partial Derivative Constraint Function Wedge Product Inverse Function Theorem Invertibility Condition 
These keywords were added by machine and not by the authors. This process is experimental and the keywords may be updated as the learning algorithm improves.

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Copyright information

© Springer-Verlag London Limited 2011

Authors and Affiliations

  1. 1.Indian Institute of Science Education and Research (Mohali)PanchkulaIndia
  2. 2.Indian Institute of Science Education and Research (Mohali)ChandigarhIndia

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