Abstract
The reaction between a reduced form of cobalamin (cobalamin(II), Cbl(II)) and periodate in alkaline medium is studied. It is shown that there is no destruction of cobalamin at the ratio of [Cbl(II)] : [IO\(_{4}^{ - }\)] = 2 : 1. The reaction mechanism includes interactions between Cbl(II) and H4IO\(_{6}^{ - }\) and H3IO\(_{6}^{{2 - }}\) leading to the formation of aquacobalamin and radicals I(VI), which rapidly oxidize the second molecule of Cbl(II) to aquacobalamin.
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Dereven’kov, I.A., Shpagilev, N.I. & Makarov, S.V. Mechanism of the Reaction between Cobalamin(II) and Periodate. Russ. J. Phys. Chem. 92, 2182–2186 (2018). https://doi.org/10.1134/S0036024418110080
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DOI: https://doi.org/10.1134/S0036024418110080