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Table 5 Calculations for determining the amount of dopants needed per brick

From: The Mars Science Laboratory Organic Check Material

Eq. Calculation Result
1 10 nmol/0.05 cm3 brick×10−9 mol/nmol×105.45 cm3 brick= 2.11×10−5 mol of each dopant per brick
2 (2.11×10−5 mol 1FN×146.17 g/mol×1000 μl/ml)/1.330 g/ml= 2.3 μl 1 FN per brick
3 2.11×10−5 mol 3 FP×196.1 g/mol×1000 mg/g= 4.14 mg 3 FP per brick
4 Ratio 1 FN/3 FP (μl/mg) = 0.56